What is the share of each heir from the inheritance of a married man who passed away and left behind four daughters, a mother, five brothers, four full sisters, and one half-sister through the father, and how is the inheritance divided?
If a man dies and leaves behind a wife, a mother, four daughters, five full brothers, four full sisters, and a paternal half-sister; the paternal half-sister receives nothing because she is excluded by the full brothers.
The inheritance is divided as follows: the wife receives one-eighth due to the presence of a lineal descendant, the mother receives one-sixth due to the presence of a lineal descendant, the daughters receive two-thirds, and the remaining portion is for the full brothers and sisters by ta'sib (residuary heirship), with the male receiving the share of two females.
Thus, the inheritance is divided into 24 parts: the wife receives 3, the mother receives 4, the daughters receive 16, and the remaining 1 part is for the full brothers and sisters, with the male receiving the share of two females.
Summarized from the full answer at Ftawy · reviewed Sep 2, 2026
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