How is the inheritance of a man who died leaving a wife, a son, two daughters, and a mother, and who has brothers and sisters, distributed?
The method of dividing the inheritance cannot be determined until the heirs are precisely enumerated. If the aforementioned heirs are the only ones, then the mother receives one-sixth due to the presence of a lineal descendant, and the wife receives one-eighth due to the presence of a lineal descendant. The remainder goes to the son and the two daughters by ta'sib (residuary heirship), with the male receiving the share of two females. The brothers and sisters receive nothing due to the presence of the son. The inheritance is divided into ninety-six shares: the mother receives sixteen shares, the wife receives twelve shares, the son receives thirty-four shares, and each daughter receives seventeen shares.
Summarized from the full answer at Ftawy · reviewed Sep 2, 2026
Read the full answer on Ftawyhttps://ftawy.com/en/questions/175140