How is the inheritance calculated if the heirs are: a husband, a mother, two full sisters, and two full paternal cousins?
If a woman dies and leaves behind a mother, a husband, two full sisters, and two paternal cousins, the inheritance is divided as follows:
The mother: One-sixth, due to the presence of more than one sister. The husband: One-half, due to the absence of any descendant heirs of the deceased. The two full sisters: Two-thirds. The two paternal cousins: They inherit nothing here, because they are 'asabah (agnate heirs) and nothing remains for them after the sharers (ashab al-furud).
The issue is one of 'awl (a proportionate reduction of shares), so the inheritance is divided into 8 shares: the mother receives one share, the husband receives 3 shares, and each sister receives two shares.
Inheritance matters must be brought before the courts for investigation before distribution.
Summarized from the full answer at Ftawy · imported
Read the full answer on Ftawyhttps://ftawy.com/en/questions/112412
Where this answer came from
- Source platform
- Ftawy
- Original fatwa ID
- 112412
- Imported
- Translation status
- Source text, unreviewed
- Read the full ruling
- Read the full answer on Ftawy