How is the estate of a man who died leaving behind a wife, three daughters, a mother, and maternal half-siblings to be divided?

The male heirs are fifteen, and the female heirs are ten. The method of distributing the inheritance cannot be clarified until they are identified. If we assume that the deceased left no heirs other than his mother, his wife, his three daughters, and his maternal half-siblings, then their prescribed shares are as follows:

The mother receives one-sixth (1/6) as a prescribed share due to the presence of lineal descendants and a group of siblings. The wife receives one-eighth (1/8) as a prescribed share due to the presence of lineal descendants. The three daughters receive two-thirds (2/3) as a prescribed share. The maternal half-siblings receive nothing because they do not inherit in the presence of daughters (they are excluded by complete exclusion).

The issue involves a 'radd' (return) to the mother and daughters. The calculation is correctly derived from one hundred and twenty. The wife receives fifteen shares. The mother receives twenty-one shares, comprising her prescribed share and the 'radd.' His three daughters receive eighty-four shares, comprising their prescribed share and the 'radd' (each daughter receiving twenty-eight shares).