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The question

How is the inheritance calculated for a man who died and left behind: two wives, four sons, and three daughters, knowing that one of the wives gave birth to two sons and two daughters, and the other to two sons and one daughter, and that one of the sons of the first wife died one year after the father, then the first wife died years later?

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Source: FtawySummarized from the full answer at Ftawy · imported Sep 2, 20261 min readAlso available in العربية
The answer

If the son and one of the wives pass away after the father, and the deceased leaves no one except those mentioned, then the two wives receive one-eighth due to the presence of a lineal descendant, in accordance with His (Allah's) saying: "But if you have a child, then for them [i.e., the wives] is one-eighth of what you leave, after any bequest you [may have] made or debt." The remainder goes to the sons and daughters by way of ta'sib (residuary heirship), with the male receiving the share of two females, due to His (Allah's) saying: "Allah instructs you concerning your children: for the male, what is equal to the share of two females." The inheritance is divided into 176 shares: 22 shares for the two wives (11 for each), 28 shares for each son, and 14 shares for each daughter. The share of the deceased wife and the deceased son is transferred to their heirs.

Summarized from the full answer at Ftawy · imported

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Source platform
Ftawy
Original fatwa ID
120614
Imported
Translation status
Source text, unreviewed
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