How is an inheritance divided in the case of a man dying and leaving behind two wives and a number of children, then one of the wives and one of her children die a short time after him?

If a man dies leaving two wives and six children (five sons and one daughter), and he has no other heirs, then the wives receive one-eighth, to be divided between them, and the remainder goes to the children, with the male receiving the share of two females. The inheritance is divided into 176 shares: the two wives receive 22 shares (11 for each), the daughter receives 14 shares, and each son receives 28 shares.

If the first wife dies, her heirs are her children from him (not the children of the second wife), and any surviving parents or her grandmother. If one of the first wife's sons dies, his inheritance passes to his heirs. If he has no children or wife, his inheritance goes to his brother. If the first wife and her son die at the same instant, the son does not inherit from his mother, and the mother's inheritance passes to her surviving son and any surviving parents or her grandmother. The son's inheritance passes to his brother if he has no child or wife.